Base | Representation |
---|---|
bin | 111110100110110001001… |
… | …000101110111101000001 |
3 | 120020021211002111210011111 |
4 | 332212301020232331001 |
5 | 1030441433413320001 |
6 | 13052230304043321 |
7 | 622553241433036 |
oct | 76466110567501 |
9 | 16207732453144 |
10 | 4302234120001 |
11 | 1409627002334 |
12 | 595975603541 |
13 | 25291174402c |
14 | 10c32d08138d |
15 | 76d9e875851 |
hex | 3e9b122ef41 |
4302234120001 has 2 divisors, whose sum is σ = 4302234120002. Its totient is φ = 4302234120000.
The previous prime is 4302234119971. The next prime is 4302234120089. The reversal of 4302234120001 is 1000214322034.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3943342066225 + 358892053776 = 1985785^2 + 599076^2 .
It is a cyclic number.
It is not a de Polignac number, because 4302234120001 - 217 = 4302233988929 is a prime.
It is not a weakly prime, because it can be changed into another prime (4302234127001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2151117060000 + 2151117060001.
It is an arithmetic number, because the mean of its divisors is an integer number (2151117060001).
Almost surely, 24302234120001 is an apocalyptic number.
It is an amenable number.
4302234120001 is a deficient number, since it is larger than the sum of its proper divisors (1).
4302234120001 is an equidigital number, since it uses as much as digits as its factorization.
4302234120001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 22.
Adding to 4302234120001 its reverse (1000214322034), we get a palindrome (5302448442035).
The spelling of 4302234120001 in words is "four trillion, three hundred two billion, two hundred thirty-four million, one hundred twenty thousand, one".
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