Base | Representation |
---|---|
bin | 110000111010010011001100… |
… | …0101101101111100111001011 |
3 | 2002102022010021210211220210002 |
4 | 1201310212120231233213023 |
5 | 422342302042121420410 |
6 | 4123002411255313215 |
7 | 156422512031062643 |
oct | 14164463055574713 |
9 | 2072263253756702 |
10 | 430225141201355 |
11 | 1150a0504297605 |
12 | 4030462137b80b |
13 | 1560a097850776 |
14 | 7835017ad7523 |
15 | 34b12236417a5 |
hex | 1874998b6f9cb |
430225141201355 has 16 divisors (see below), whose sum is σ = 523542744463104. Its totient is φ = 339331751172960.
The previous prime is 430225141201343. The next prime is 430225141201367. The reversal of 430225141201355 is 553102141522034.
It is an interprime number because it is at equal distance from previous prime (430225141201343) and next prime (430225141201367).
It is not a de Polignac number, because 430225141201355 - 26 = 430225141201291 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 201453584 + ... + 203577986.
It is an arithmetic number, because the mean of its divisors is an integer number (32721421528944).
Almost surely, 2430225141201355 is an apocalyptic number.
430225141201355 is a deficient number, since it is larger than the sum of its proper divisors (93317603261749).
430225141201355 is a wasteful number, since it uses less digits than its factorization.
430225141201355 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2694946.
The product of its (nonzero) digits is 144000, while the sum is 38.
Adding to 430225141201355 its reverse (553102141522034), we get a palindrome (983327282723389).
The spelling of 430225141201355 in words is "four hundred thirty trillion, two hundred twenty-five billion, one hundred forty-one million, two hundred one thousand, three hundred fifty-five".
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