Base | Representation |
---|---|
bin | 111110100111101101000… |
… | …101110111011100101011 |
3 | 120020101102012020211221021 |
4 | 332213231011313130223 |
5 | 1031001013420020243 |
6 | 13052514155353311 |
7 | 622620204330454 |
oct | 76475505673453 |
9 | 16211365224837 |
10 | 4303240001323 |
11 | 1409aa288290a |
12 | 595bb6452837 |
13 | 252a41c60193 |
14 | 10c3c68c012b |
15 | 76e0cd196ed |
hex | 3e9ed17772b |
4303240001323 has 8 divisors (see below), whose sum is σ = 4408455476880. Its totient is φ = 4198036830720.
The previous prime is 4303240001251. The next prime is 4303240001363. The reversal of 4303240001323 is 3231000423034.
4303240001323 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 4303240001323 - 29 = 4303240000811 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (4303240001363) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2366278 + ... + 3769051.
It is an arithmetic number, because the mean of its divisors is an integer number (551056934610).
Almost surely, 24303240001323 is an apocalyptic number.
4303240001323 is a deficient number, since it is larger than the sum of its proper divisors (105215475557).
4303240001323 is a wasteful number, since it uses less digits than its factorization.
4303240001323 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6152477.
The product of its (nonzero) digits is 5184, while the sum is 25.
Adding to 4303240001323 its reverse (3231000423034), we get a palindrome (7534240424357).
The spelling of 4303240001323 in words is "four trillion, three hundred three billion, two hundred forty million, one thousand, three hundred twenty-three".
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