Base | Representation |
---|---|
bin | 10011100100101110000010… |
… | …11010000110111101000010 |
3 | 12122101212210111020220111121 |
4 | 21302113001122012331002 |
5 | 21120204243200321010 |
6 | 231313422134102454 |
7 | 12031522305216133 |
oct | 1162270132067502 |
9 | 178355714226447 |
10 | 43043112120130 |
11 | 127955327297a1 |
12 | 49b20631aaa2a |
13 | 1b02c42b59805 |
14 | a8b42500dc8a |
15 | 4e99b42873da |
hex | 2725c1686f42 |
43043112120130 has 32 divisors (see below), whose sum is σ = 79660167890688. Its totient is φ = 16735329302400.
The previous prime is 43043112120119. The next prime is 43043112120181. The reversal of 43043112120130 is 3102121134034.
It is a super-3 number, since 3×430431121201303 (a number of 42 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 43043112120095 and 43043112120104.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 193584832 + ... + 193807051.
It is an arithmetic number, because the mean of its divisors is an integer number (2489380246584).
Almost surely, 243043112120130 is an apocalyptic number.
43043112120130 is a deficient number, since it is larger than the sum of its proper divisors (36617055770558).
43043112120130 is a wasteful number, since it uses less digits than its factorization.
43043112120130 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 387392202.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 43043112120130 its reverse (3102121134034), we get a palindrome (46145233254164).
The spelling of 43043112120130 in words is "forty-three trillion, forty-three billion, one hundred twelve million, one hundred twenty thousand, one hundred thirty".
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