Base | Representation |
---|---|
bin | 111110101001010110101… |
… | …011011010100011100101 |
3 | 120020112222122112212121112 |
4 | 332221112223122203211 |
5 | 1031013130412432013 |
6 | 13053410035554405 |
7 | 623012124401210 |
oct | 76512653324345 |
9 | 16215878485545 |
10 | 4305011452133 |
11 | 140a821808047 |
12 | 59640b75ba05 |
13 | 252c64c65722 |
14 | 10c513c84777 |
15 | 76eb35d3ba8 |
hex | 3ea56ada8e5 |
4305011452133 has 16 divisors (see below), whose sum is σ = 4936261962240. Its totient is φ = 3677839948800.
The previous prime is 4305011452087. The next prime is 4305011452151. The reversal of 4305011452133 is 3312541105034.
It is a cyclic number.
It is not a de Polignac number, because 4305011452133 - 230 = 4303937710309 is a prime.
It is a Curzon number.
It is a self number, because there is not a number n which added to its sum of digits gives 4305011452133.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4305011451133) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2381573 + ... + 3779141.
It is an arithmetic number, because the mean of its divisors is an integer number (308516372640).
Almost surely, 24305011452133 is an apocalyptic number.
It is an amenable number.
4305011452133 is a deficient number, since it is larger than the sum of its proper divisors (631250510107).
4305011452133 is a wasteful number, since it uses less digits than its factorization.
4305011452133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1399028.
The product of its (nonzero) digits is 21600, while the sum is 32.
Adding to 4305011452133 its reverse (3312541105034), we get a palindrome (7617552557167).
The spelling of 4305011452133 in words is "four trillion, three hundred five billion, eleven million, four hundred fifty-two thousand, one hundred thirty-three".
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