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4305054454553 is a prime number
BaseRepresentation
bin111110101001011001001…
…111011101001100011001
3120020120002122110121211202
4332221121033131030121
51031013222420021203
613053414213403545
7623013156042536
oct76513117351431
916216078417752
104305054454553
11140a844009436
125964220395b5
13252c70b40a48
1410c519879d8d
1576eb727a388
hex3ea593dd319

4305054454553 has 2 divisors, whose sum is σ = 4305054454554. Its totient is φ = 4305054454552.

The previous prime is 4305054454531. The next prime is 4305054454573. The reversal of 4305054454553 is 3554544505034.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2394610787209 + 1910443667344 = 1547453^2 + 1382188^2 .

It is a cyclic number.

It is not a de Polignac number, because 4305054454553 - 214 = 4305054438169 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 4305054454498 and 4305054454507.

It is not a weakly prime, because it can be changed into another prime (4305054454573) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2152527227276 + 2152527227277.

It is an arithmetic number, because the mean of its divisors is an integer number (2152527227277).

Almost surely, 24305054454553 is an apocalyptic number.

It is an amenable number.

4305054454553 is a deficient number, since it is larger than the sum of its proper divisors (1).

4305054454553 is an equidigital number, since it uses as much as digits as its factorization.

4305054454553 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7200000, while the sum is 47.

Adding to 4305054454553 its reverse (3554544505034), we get a palindrome (7859598959587).

The spelling of 4305054454553 in words is "four trillion, three hundred five billion, fifty-four million, four hundred fifty-four thousand, five hundred fifty-three".