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43065302113 = 107402479459
BaseRepresentation
bin101000000110111001…
…000101110001100001
311010011021222000111101
4220012321011301201
51201144204131423
631441154514401
73053125012441
oct500671056141
9133137860441
1043065302113
111729a270979
12841a595a01
1340a414c1b2
142127732121
1511c0b797ad
hexa06e45c61

43065302113 has 4 divisors (see below), whose sum is σ = 43467781680. Its totient is φ = 42662822548.

The previous prime is 43065302089. The next prime is 43065302141. The reversal of 43065302113 is 31120356034.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 43065302113 - 229 = 42528431201 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (43065302213) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 201239623 + ... + 201239836.

It is an arithmetic number, because the mean of its divisors is an integer number (10866945420).

Almost surely, 243065302113 is an apocalyptic number.

It is an amenable number.

43065302113 is a deficient number, since it is larger than the sum of its proper divisors (402479567).

43065302113 is a wasteful number, since it uses less digits than its factorization.

43065302113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 402479566.

The product of its (nonzero) digits is 6480, while the sum is 28.

Adding to 43065302113 its reverse (31120356034), we get a palindrome (74185658147).

The spelling of 43065302113 in words is "forty-three billion, sixty-five million, three hundred two thousand, one hundred thirteen".

Divisors: 1 107 402479459 43065302113