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43101421401 = 314367140467
BaseRepresentation
bin101000001001000010…
…110111111101011001
311010020210221001211210
4220021002313331121
51201232430441101
631444525013333
73054044015463
oct501102677531
9133223831753
1043101421401
11173086a0925
12842a6b4249
1340ab78755c
14212c455133
1511c3e117d6
hexa090b7f59

43101421401 has 4 divisors (see below), whose sum is σ = 57468561872. Its totient is φ = 28734280932.

The previous prime is 43101421367. The next prime is 43101421457. The reversal of 43101421401 is 10412410134.

43101421401 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 43101421401 - 29 = 43101420889 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (43101421201) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7183570231 + ... + 7183570236.

It is an arithmetic number, because the mean of its divisors is an integer number (14367140468).

Almost surely, 243101421401 is an apocalyptic number.

It is an amenable number.

43101421401 is a deficient number, since it is larger than the sum of its proper divisors (14367140471).

43101421401 is a wasteful number, since it uses less digits than its factorization.

43101421401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14367140470.

The product of its (nonzero) digits is 384, while the sum is 21.

Adding to 43101421401 its reverse (10412410134), we get a palindrome (53513831535).

The spelling of 43101421401 in words is "forty-three billion, one hundred one million, four hundred twenty-one thousand, four hundred one".

Divisors: 1 3 14367140467 43101421401