Base | Representation |
---|---|
bin | 110001000000000110011101… |
… | …1000101111110110111011010 |
3 | 2002112010100020112200121121202 |
4 | 1202000030323011332313122 |
5 | 422443332421202222132 |
6 | 4124412550044034202 |
7 | 156534225506422532 |
oct | 14200147305766732 |
9 | 2075110215617552 |
10 | 431022434414042 |
11 | 115378651549999 |
12 | 40413051232962 |
13 | 15667319aa8233 |
14 | 78618507804c2 |
15 | 34c6d38eac762 |
hex | 188033b17edda |
431022434414042 has 4 divisors (see below), whose sum is σ = 646533651621066. Its totient is φ = 215511217207020.
The previous prime is 431022434413999. The next prime is 431022434414051. The reversal of 431022434414042 is 240414434220134.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 330981210166321 + 100041224247721 = 18192889^2 + 10002061^2 .
It is a junction number, because it is equal to n+sod(n) for n = 431022434413987 and 431022434414005.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107755608603509 + ... + 107755608603512.
Almost surely, 2431022434414042 is an apocalyptic number.
431022434414042 is a deficient number, since it is larger than the sum of its proper divisors (215511217207024).
431022434414042 is a wasteful number, since it uses less digits than its factorization.
431022434414042 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 215511217207023.
The product of its (nonzero) digits is 294912, while the sum is 38.
Adding to 431022434414042 its reverse (240414434220134), we get a palindrome (671436868634176).
The spelling of 431022434414042 in words is "four hundred thirty-one trillion, twenty-two billion, four hundred thirty-four million, four hundred fourteen thousand, forty-two".
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