Base | Representation |
---|---|
bin | 111110101111000011101… |
… | …000010001001001011001 |
3 | 120021010210100210022222012 |
4 | 332233003220101021121 |
5 | 1031113200340423001 |
6 | 13100301402035305 |
7 | 623316633005540 |
oct | 76570350211131 |
9 | 16233710708865 |
10 | 4311134311001 |
11 | 1412383a22591 |
12 | 59763a1a8b35 |
13 | 2536cc61973b |
14 | 10c935115157 |
15 | 77220dd92bb |
hex | 3ebc3a11259 |
4311134311001 has 16 divisors (see below), whose sum is σ = 4965756300288. Its totient is φ = 3666259098000.
The previous prime is 4311134310913. The next prime is 4311134311013. The reversal of 4311134311001 is 1001134311134.
4311134311001 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4311134311001 is a prime.
It is not an unprimeable number, because it can be changed into a prime (4311134311051) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1657355 + ... + 3371808.
It is an arithmetic number, because the mean of its divisors is an integer number (310359768768).
Almost surely, 24311134311001 is an apocalyptic number.
It is an amenable number.
4311134311001 is a deficient number, since it is larger than the sum of its proper divisors (654621989287).
4311134311001 is a wasteful number, since it uses less digits than its factorization.
4311134311001 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5030132.
The product of its (nonzero) digits is 432, while the sum is 23.
Adding to 4311134311001 its reverse (1001134311134), we get a palindrome (5312268622135).
The spelling of 4311134311001 in words is "four trillion, three hundred eleven billion, one hundred thirty-four million, three hundred eleven thousand, one".
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