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43112048474857 is a prime number
BaseRepresentation
bin10011100110101110011100…
…10101011011101011101001
312122122110201210011120100211
421303113032111123223221
521122321433402143412
6231405222431301121
712036512515446145
oct1163271625335351
9178573653146324
1043112048474857
111281179848738a
124a034a197a7a1
131b095aab11a5b
14a908c466c225
154eb69b2e3ca7
hex2735ce55bae9

43112048474857 has 2 divisors, whose sum is σ = 43112048474858. Its totient is φ = 43112048474856.

The previous prime is 43112048474849. The next prime is 43112048474897. The reversal of 43112048474857 is 75847484021134.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 21871186168896 + 21240862305961 = 4676664^2 + 4608781^2 .

It is a cyclic number.

It is not a de Polignac number, because 43112048474857 - 23 = 43112048474849 is a prime.

It is a super-2 number, since 2×431120484748572 (a number of 28 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (43112048474897) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21556024237428 + 21556024237429.

It is an arithmetic number, because the mean of its divisors is an integer number (21556024237429).

Almost surely, 243112048474857 is an apocalyptic number.

It is an amenable number.

43112048474857 is a deficient number, since it is larger than the sum of its proper divisors (1).

43112048474857 is an equidigital number, since it uses as much as digits as its factorization.

43112048474857 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24084480, while the sum is 58.

The spelling of 43112048474857 in words is "forty-three trillion, one hundred twelve billion, forty-eight million, four hundred seventy-four thousand, eight hundred fifty-seven".