Base | Representation |
---|---|
bin | 110001000001011001101010… |
… | …1101001100110100110001001 |
3 | 2002112202102110112012212201201 |
4 | 1202002303111221212212021 |
5 | 423004244344000232332 |
6 | 4125031021011544201 |
7 | 156553152520260304 |
oct | 14202632551464611 |
9 | 2075672415185651 |
10 | 431201121102217 |
11 | 1154374065214a4 |
12 | 404417babbb061 |
13 | 1567b12560369b |
14 | 786a361d91b3b |
15 | 34cb7e62465e7 |
hex | 1882cd5a66989 |
431201121102217 has 2 divisors, whose sum is σ = 431201121102218. Its totient is φ = 431201121102216.
The previous prime is 431201121102119. The next prime is 431201121102221. The reversal of 431201121102217 is 712201121102134.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 405757409583241 + 25443711518976 = 20143421^2 + 5044176^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-431201121102217 is a prime.
It is not a weakly prime, because it can be changed into another prime (431201121102247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 215600560551108 + 215600560551109.
It is an arithmetic number, because the mean of its divisors is an integer number (215600560551109).
Almost surely, 2431201121102217 is an apocalyptic number.
It is an amenable number.
431201121102217 is a deficient number, since it is larger than the sum of its proper divisors (1).
431201121102217 is an equidigital number, since it uses as much as digits as its factorization.
431201121102217 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1344, while the sum is 28.
The spelling of 431201121102217 in words is "four hundred thirty-one trillion, two hundred one billion, one hundred twenty-one million, one hundred two thousand, two hundred seventeen".
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