Base | Representation |
---|---|
bin | 111110101111110111111… |
… | …101100101101110010001 |
3 | 120021020001112220120202201 |
4 | 332233313331211232101 |
5 | 1031122000123044122 |
6 | 13100524444443201 |
7 | 623350453634533 |
oct | 76576775455621 |
9 | 16236045816681 |
10 | 4312012315537 |
11 | 14127945a1373 |
12 | 597844249501 |
13 | 25380c4b1654 |
14 | 10c9b9987853 |
15 | 7727301da27 |
hex | 3ebf7f65b91 |
4312012315537 has 2 divisors, whose sum is σ = 4312012315538. Its totient is φ = 4312012315536.
The previous prime is 4312012315529. The next prime is 4312012315549. The reversal of 4312012315537 is 7355132102134.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3395060519761 + 916951795776 = 1842569^2 + 957576^2 .
It is a cyclic number.
It is not a de Polignac number, because 4312012315537 - 23 = 4312012315529 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 4312012315496 and 4312012315505.
It is not a weakly prime, because it can be changed into another prime (4312012315577) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2156006157768 + 2156006157769.
It is an arithmetic number, because the mean of its divisors is an integer number (2156006157769).
Almost surely, 24312012315537 is an apocalyptic number.
It is an amenable number.
4312012315537 is a deficient number, since it is larger than the sum of its proper divisors (1).
4312012315537 is an equidigital number, since it uses as much as digits as its factorization.
4312012315537 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 75600, while the sum is 37.
The spelling of 4312012315537 in words is "four trillion, three hundred twelve billion, twelve million, three hundred fifteen thousand, five hundred thirty-seven".
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