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4312200014131 is a prime number
BaseRepresentation
bin111110110000000011001…
…001100110100100110011
3120021020112122002122211111
4332300003021212210303
51031122341200423011
613100555231454151
7623355223226002
oct76600311464463
916236478078744
104312200014131
111412880542079
12597897087357
1325383c34c6c9
1410c9d6886c39
1577284748121
hex3ec03266933

4312200014131 has 2 divisors, whose sum is σ = 4312200014132. Its totient is φ = 4312200014130.

The previous prime is 4312200014113. The next prime is 4312200014189. The reversal of 4312200014131 is 1314100022134.

Together with previous prime (4312200014113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 4312200014131 - 29 = 4312200013619 is a prime.

It is a super-2 number, since 2×43122000141312 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (4312200014531) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2156100007065 + 2156100007066.

It is an arithmetic number, because the mean of its divisors is an integer number (2156100007066).

Almost surely, 24312200014131 is an apocalyptic number.

4312200014131 is a deficient number, since it is larger than the sum of its proper divisors (1).

4312200014131 is an equidigital number, since it uses as much as digits as its factorization.

4312200014131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 4312200014131 its reverse (1314100022134), we get a palindrome (5626300036265).

The spelling of 4312200014131 in words is "four trillion, three hundred twelve billion, two hundred million, fourteen thousand, one hundred thirty-one".