Base | Representation |
---|---|
bin | 111110110000000100011… |
… | …010000101011100100011 |
3 | 120021020121002210112210201 |
4 | 332300010122011130203 |
5 | 1031122412101041344 |
6 | 13101001304010031 |
7 | 623355600450055 |
oct | 76600432053443 |
9 | 16236532715721 |
10 | 4312221112099 |
11 | 141289144230a |
12 | 5978a2160917 |
13 | 253843828804 |
14 | 10c9d95b98d5 |
15 | 772865144d4 |
hex | 3ec04685723 |
4312221112099 has 4 divisors (see below), whose sum is σ = 4312228761720. Its totient is φ = 4312213462480.
The previous prime is 4312221112049. The next prime is 4312221112109. The reversal of 4312221112099 is 9902111222134.
4312221112099 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 4312221112099 - 229 = 4311684241187 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (4312221112019) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2905597 + ... + 4131214.
It is an arithmetic number, because the mean of its divisors is an integer number (1078057190430).
Almost surely, 24312221112099 is an apocalyptic number.
4312221112099 is a deficient number, since it is larger than the sum of its proper divisors (7649621).
4312221112099 is an equidigital number, since it uses as much as digits as its factorization.
4312221112099 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7649620.
The product of its (nonzero) digits is 15552, while the sum is 37.
The spelling of 4312221112099 in words is "four trillion, three hundred twelve billion, two hundred twenty-one million, one hundred twelve thousand, ninety-nine".
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