Base | Representation |
---|---|
bin | 10011100111000010111001… |
… | …11110000110001110000010 |
3 | 12122200112002012112201002121 |
4 | 21303201130332012032002 |
5 | 21123011432021342424 |
6 | 231414240330234454 |
7 | 12040351630166422 |
oct | 1163413476061602 |
9 | 178615065481077 |
10 | 43123031434114 |
11 | 12816414036215 |
12 | 4a05647b85a2a |
13 | 1b0a63b350c08 |
14 | a91247184482 |
15 | 4ebae0618ee4 |
hex | 27385cf86382 |
43123031434114 has 4 divisors (see below), whose sum is σ = 64684547151174. Its totient is φ = 21561515717056.
The previous prime is 43123031434111. The next prime is 43123031434127. The reversal of 43123031434114 is 41143413032134.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 41399894775625 + 1723136658489 = 6434275^2 + 1312683^2 .
It is a self number, because there is not a number n which added to its sum of digits gives 43123031434114.
It is not an unprimeable number, because it can be changed into a prime (43123031434111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10780757858527 + ... + 10780757858530.
Almost surely, 243123031434114 is an apocalyptic number.
43123031434114 is a deficient number, since it is larger than the sum of its proper divisors (21561515717060).
43123031434114 is a wasteful number, since it uses less digits than its factorization.
43123031434114 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 21561515717059.
The product of its (nonzero) digits is 41472, while the sum is 34.
Adding to 43123031434114 its reverse (41143413032134), we get a palindrome (84266444466248).
The spelling of 43123031434114 in words is "forty-three trillion, one hundred twenty-three billion, thirty-one million, four hundred thirty-four thousand, one hundred fourteen".
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