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43123031434114 = 221561515717057
BaseRepresentation
bin10011100111000010111001…
…11110000110001110000010
312122200112002012112201002121
421303201130332012032002
521123011432021342424
6231414240330234454
712040351630166422
oct1163413476061602
9178615065481077
1043123031434114
1112816414036215
124a05647b85a2a
131b0a63b350c08
14a91247184482
154ebae0618ee4
hex27385cf86382

43123031434114 has 4 divisors (see below), whose sum is σ = 64684547151174. Its totient is φ = 21561515717056.

The previous prime is 43123031434111. The next prime is 43123031434127. The reversal of 43123031434114 is 41143413032134.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 41399894775625 + 1723136658489 = 6434275^2 + 1312683^2 .

It is a self number, because there is not a number n which added to its sum of digits gives 43123031434114.

It is not an unprimeable number, because it can be changed into a prime (43123031434111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10780757858527 + ... + 10780757858530.

Almost surely, 243123031434114 is an apocalyptic number.

43123031434114 is a deficient number, since it is larger than the sum of its proper divisors (21561515717060).

43123031434114 is a wasteful number, since it uses less digits than its factorization.

43123031434114 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 21561515717059.

The product of its (nonzero) digits is 41472, while the sum is 34.

Adding to 43123031434114 its reverse (41143413032134), we get a palindrome (84266444466248).

The spelling of 43123031434114 in words is "forty-three trillion, one hundred twenty-three billion, thirty-one million, four hundred thirty-four thousand, one hundred fourteen".

Divisors: 1 2 21561515717057 43123031434114