Base | Representation |
---|---|
bin | 1100100011010111011… |
… | …11111000001001001001 |
3 | 1112020021100101210222221 |
4 | 12101223233320021021 |
5 | 24031302414124231 |
6 | 530045531014041 |
7 | 43106061162025 |
oct | 6215357701111 |
9 | 1466240353887 |
10 | 431304442441 |
11 | 156a08128334 |
12 | 6b70ab9a321 |
13 | 31897035472 |
14 | 16c37967385 |
15 | b344cddd11 |
hex | 646bbf8249 |
431304442441 has 2 divisors, whose sum is σ = 431304442442. Its totient is φ = 431304442440.
The previous prime is 431304442417. The next prime is 431304442483. The reversal of 431304442441 is 144244403134.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 420189168400 + 11115274041 = 648220^2 + 105429^2 .
It is a cyclic number.
It is not a de Polignac number, because 431304442441 - 29 = 431304441929 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 431304442397 and 431304442406.
It is not a weakly prime, because it can be changed into another prime (431304142441) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 215652221220 + 215652221221.
It is an arithmetic number, because the mean of its divisors is an integer number (215652221221).
Almost surely, 2431304442441 is an apocalyptic number.
It is an amenable number.
431304442441 is a deficient number, since it is larger than the sum of its proper divisors (1).
431304442441 is an equidigital number, since it uses as much as digits as its factorization.
431304442441 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 73728, while the sum is 34.
Adding to 431304442441 its reverse (144244403134), we get a palindrome (575548845575).
The spelling of 431304442441 in words is "four hundred thirty-one billion, three hundred four million, four hundred forty-two thousand, four hundred forty-one".
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