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4313100660161 = 27115915500591
BaseRepresentation
bin111110110000111000110…
…101010010110111000001
3120021022212101211012220212
4332300320311102313001
51031131212232111121
613101224443443505
7623416440465116
oct76607065226701
916238771735825
104313100660161
1114131a2975837
12597aa8826595
13253953b11157
1410ca8033090d
15772d885125b
hex3ec38d52dc1

4313100660161 has 4 divisors (see below), whose sum is σ = 4329016161024. Its totient is φ = 4297185159300.

The previous prime is 4313100660149. The next prime is 4313100660223. The reversal of 4313100660161 is 1610660013134.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4313100660161 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4313100660131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7957750025 + ... + 7957750566.

It is an arithmetic number, because the mean of its divisors is an integer number (1082254040256).

Almost surely, 24313100660161 is an apocalyptic number.

It is an amenable number.

4313100660161 is a deficient number, since it is larger than the sum of its proper divisors (15915500863).

4313100660161 is a wasteful number, since it uses less digits than its factorization.

4313100660161 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15915500862.

The product of its (nonzero) digits is 7776, while the sum is 32.

Adding to 4313100660161 its reverse (1610660013134), we get a palindrome (5923760673295).

The spelling of 4313100660161 in words is "four trillion, three hundred thirteen billion, one hundred million, six hundred sixty thousand, one hundred sixty-one".

Divisors: 1 271 15915500591 4313100660161