Base | Representation |
---|---|
bin | 110001000010010011100110… |
… | …1111110000100001011010001 |
3 | 2002120012022121221011211112112 |
4 | 1202010213031332010023101 |
5 | 423013314204323100423 |
6 | 4125204115343435105 |
7 | 156565146062066303 |
oct | 14204471576041321 |
9 | 2076168557154475 |
10 | 431325546300113 |
11 | 115485156286263 |
12 | 404619448b5a95 |
13 | 15689a9453403a |
14 | 78723a6cd1973 |
15 | 34ceb79961a78 |
hex | 18849cdf842d1 |
431325546300113 has 4 divisors (see below), whose sum is σ = 431641073401920. Its totient is φ = 431010019198308.
The previous prime is 431325546300091. The next prime is 431325546300191. The reversal of 431325546300113 is 311003645523134.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 431325546300113 - 214 = 431325546283729 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (431325546300193) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 157763548853 + ... + 157763551586.
It is an arithmetic number, because the mean of its divisors is an integer number (107910268350480).
Almost surely, 2431325546300113 is an apocalyptic number.
It is an amenable number.
431325546300113 is a deficient number, since it is larger than the sum of its proper divisors (315527101807).
431325546300113 is a wasteful number, since it uses less digits than its factorization.
431325546300113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 315527101806.
The product of its (nonzero) digits is 388800, while the sum is 41.
The spelling of 431325546300113 in words is "four hundred thirty-one trillion, three hundred twenty-five billion, five hundred forty-six million, three hundred thousand, one hundred thirteen".
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