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4313422014403 = 4986438650321
BaseRepresentation
bin111110110001001011111…
…111001010011111000011
3120021100200210111201001211
4332301023333022133003
51031132342013430103
613101320403310551
7623430422114005
oct76611377123703
916240623451054
104313422014403
111413348304a57
12597b7837b457
132539a55778a8
1410cab0ca2375
1577306b7c36d
hex3ec4bfca7c3

4313422014403 has 4 divisors (see below), whose sum is σ = 4313431163368. Its totient is φ = 4313412865440.

The previous prime is 4313422014401. The next prime is 4313422014493. The reversal of 4313422014403 is 3044102243134.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 4313422014403 - 21 = 4313422014401 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4313422014401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3826518 + ... + 4823803.

It is an arithmetic number, because the mean of its divisors is an integer number (1078357790842).

Almost surely, 24313422014403 is an apocalyptic number.

4313422014403 is a deficient number, since it is larger than the sum of its proper divisors (9148965).

4313422014403 is an equidigital number, since it uses as much as digits as its factorization.

4313422014403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9148964.

The product of its (nonzero) digits is 27648, while the sum is 31.

Adding to 4313422014403 its reverse (3044102243134), we get a palindrome (7357524257537).

The spelling of 4313422014403 in words is "four trillion, three hundred thirteen billion, four hundred twenty-two million, fourteen thousand, four hundred three".

Divisors: 1 498643 8650321 4313422014403