4314002240113 has 4 divisors (see below), whose sum is σ = 4414327873648. Its totient is φ = 4213676606580.

The previous prime is 4314002240099. The next prime is 4314002240129. The reversal of 4314002240113 is 3110422004134.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 4314002240113 - 2²⁵ = 4313968685681 is a prime.

It is a super-2 number, since 2×4314002240113² (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4314002240413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 50162816703 + ... + 50162816788.

It is an arithmetic number, because the mean of its divisors is an integer number (1103581968412).

Almost surely, 2^{4314002240113} is an apocalyptic number.

4314002240113 is a gapful number since it is divisible by the number (43) formed by its first and last digit.

It is an amenable number.

4314002240113 is a deficient number, since it is larger than the sum of its proper divisors (100325633535).

4314002240113 is a wasteful number, since it uses less digits than its factorization.

4314002240113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 100325633534.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 4314002240113 its reverse (3110422004134), we get a palindrome (7424424244247).

The spelling of 4314002240113 in words is "four trillion, three hundred fourteen billion, two million, two hundred forty thousand, one hundred thirteen".