Base | Representation |
---|---|
bin | 101000001011010110… |
… | …100000000011101011 |
3 | 11010100111202012110021 |
4 | 220023112200003223 |
5 | 1201322332331221 |
6 | 31452430301311 |
7 | 3055023655654 |
oct | 501326400353 |
9 | 133314665407 |
10 | 43140120811 |
11 | 17328523307 |
12 | 843b657837 |
13 | 40b67b7108 |
14 | 213364a52b |
15 | 11c7508041 |
hex | a0b5a00eb |
43140120811 has 2 divisors, whose sum is σ = 43140120812. Its totient is φ = 43140120810.
The previous prime is 43140120797. The next prime is 43140120823. The reversal of 43140120811 is 11802104134.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 43140120811 - 221 = 43138023659 is a prime.
It is a super-2 number, since 2×431401208112 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (43140120871) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21570060405 + 21570060406.
It is an arithmetic number, because the mean of its divisors is an integer number (21570060406).
Almost surely, 243140120811 is an apocalyptic number.
43140120811 is a deficient number, since it is larger than the sum of its proper divisors (1).
43140120811 is an equidigital number, since it uses as much as digits as its factorization.
43140120811 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 768, while the sum is 25.
Adding to 43140120811 its reverse (11802104134), we get a palindrome (54942224945).
The spelling of 43140120811 in words is "forty-three billion, one hundred forty million, one hundred twenty thousand, eight hundred eleven".
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