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4314203123011 = 6176992225483
BaseRepresentation
bin111110110001111010100…
…010110110110101000011
3120021102201020022010122021
4332301322202312311003
51031140441444414021
613101530105222311
7623455655326405
oct76617242666503
916242636263567
104314203123011
111413709212461
12598155a91997
13253a9b344b32
1410cb46910b75
1577350521c41
hex3ec7a8b6d43

4314203123011 has 4 divisors (see below), whose sum is σ = 4321195349112. Its totient is φ = 4307210896912.

The previous prime is 4314203123003. The next prime is 4314203123039. The reversal of 4314203123011 is 1103213024134.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 4314203123011 - 23 = 4314203123003 is a prime.

It is a super-2 number, since 2×43142031230112 (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4314203123411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3496112125 + ... + 3496113358.

It is an arithmetic number, because the mean of its divisors is an integer number (1080298837278).

Almost surely, 24314203123011 is an apocalyptic number.

4314203123011 is a deficient number, since it is larger than the sum of its proper divisors (6992226101).

4314203123011 is an equidigital number, since it uses as much as digits as its factorization.

4314203123011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6992226100.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 4314203123011 its reverse (1103213024134), we get a palindrome (5417416147145).

The spelling of 4314203123011 in words is "four trillion, three hundred fourteen billion, two hundred three million, one hundred twenty-three thousand, eleven".

Divisors: 1 617 6992225483 4314203123011