43143412132001 has 4 divisors (see below), whose sum is σ = 43369293871104. Its totient is φ = 42917530392900.

The previous prime is 43143412131979. The next prime is 43143412132021. The reversal of 43143412132001 is 10023121434134.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 43143412132001 - 2³⁸ = 42868534225057 is a prime.

It is a super-2 number, since 2×43143412132001² (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (43143412132021) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 112940869265 + ... + 112940869646.

It is an arithmetic number, because the mean of its divisors is an integer number (10842323467776).

Almost surely, 2^{43143412132001} is an apocalyptic number.

It is an amenable number.

43143412132001 is a deficient number, since it is larger than the sum of its proper divisors (225881739103).

43143412132001 is a wasteful number, since it uses less digits than its factorization.

43143412132001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 225881739102.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 43143412132001 its reverse (10023121434134), we get a palindrome (53166533566135).

The spelling of 43143412132001 in words is "forty-three trillion, one hundred forty-three billion, four hundred twelve million, one hundred thirty-two thousand, one".