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43143421105417 is a prime number
BaseRepresentation
bin10011100111101000111000…
…10010100001010100001001
312122202110201012022022212211
421303310130102201110021
521123330211300333132
6231431451455505121
712042003123426313
oct1163643422412411
9178673635268784
1043143421105417
1112824027516036
124a095985281a1
131b0c53a691a89
14a9221d1027b3
154ec3d56a8147
hex273d1c4a1509

43143421105417 has 2 divisors, whose sum is σ = 43143421105418. Its totient is φ = 43143421105416.

The previous prime is 43143421105397. The next prime is 43143421105439. The reversal of 43143421105417 is 71450112434134.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 25091493557881 + 18051927547536 = 5009141^2 + 4248756^2 .

It is a cyclic number.

It is not a de Polignac number, because 43143421105417 - 223 = 43143412716809 is a prime.

It is a super-2 number, since 2×431434211054172 (a number of 28 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 43143421105417.

It is not a weakly prime, because it can be changed into another prime (43143421195417) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21571710552708 + 21571710552709.

It is an arithmetic number, because the mean of its divisors is an integer number (21571710552709).

Almost surely, 243143421105417 is an apocalyptic number.

It is an amenable number.

43143421105417 is a deficient number, since it is larger than the sum of its proper divisors (1).

43143421105417 is an equidigital number, since it uses as much as digits as its factorization.

43143421105417 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 161280, while the sum is 40.

The spelling of 43143421105417 in words is "forty-three trillion, one hundred forty-three billion, four hundred twenty-one million, one hundred five thousand, four hundred seventeen".