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431441059657 is a prime number
BaseRepresentation
bin1100100011100111110…
…01000001111101001001
31112020121212110200120211
412101303321001331021
524032042402402112
6530111251121121
743112340332656
oct6216371017511
91466555420524
10431441059657
11156a78259923
126b7488a31a1
13318b9429b5a
1416c4bb6ac2d
15b351cc80a7
hex6473e41f49

431441059657 has 2 divisors, whose sum is σ = 431441059658. Its totient is φ = 431441059656.

The previous prime is 431441059619. The next prime is 431441059663. The reversal of 431441059657 is 756950144134.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 270203475721 + 161237583936 = 519811^2 + 401544^2 .

It is a cyclic number.

It is not a de Polignac number, because 431441059657 - 223 = 431432671049 is a prime.

It is a super-3 number, since 3×4314410596573 (a number of 36 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a self number, because there is not a number n which added to its sum of digits gives 431441059657.

It is not a weakly prime, because it can be changed into another prime (431441059607) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 215720529828 + 215720529829.

It is an arithmetic number, because the mean of its divisors is an integer number (215720529829).

Almost surely, 2431441059657 is an apocalyptic number.

It is an amenable number.

431441059657 is a deficient number, since it is larger than the sum of its proper divisors (1).

431441059657 is an equidigital number, since it uses as much as digits as its factorization.

431441059657 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1814400, while the sum is 49.

The spelling of 431441059657 in words is "four hundred thirty-one billion, four hundred forty-one million, fifty-nine thousand, six hundred fifty-seven".