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4314429013051 is a prime number
BaseRepresentation
bin111110110010001000000…
…000100011110000111011
3120021110021222100112112001
4332302020000203300323
51031141422311404201
613102004335001431
7623464400344063
oct76621000436073
916243258315461
104314429013051
111413814778a43
125981b9669277
13253b06095491
1410cb689123a3
1577365292301
hex3ec88023c3b

4314429013051 has 2 divisors, whose sum is σ = 4314429013052. Its totient is φ = 4314429013050.

The previous prime is 4314429013021. The next prime is 4314429013057. The reversal of 4314429013051 is 1503109244134.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 4314429013051 - 25 = 4314429013019 is a prime.

It is a super-3 number, since 3×43144290130513 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a self number, because there is not a number n which added to its sum of digits gives 4314429013051.

It is not a weakly prime, because it can be changed into another prime (4314429013057) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2157214506525 + 2157214506526.

It is an arithmetic number, because the mean of its divisors is an integer number (2157214506526).

Almost surely, 24314429013051 is an apocalyptic number.

4314429013051 is a deficient number, since it is larger than the sum of its proper divisors (1).

4314429013051 is an equidigital number, since it uses as much as digits as its factorization.

4314429013051 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 51840, while the sum is 37.

The spelling of 4314429013051 in words is "four trillion, three hundred fourteen billion, four hundred twenty-nine million, thirteen thousand, fifty-one".