Base | Representation |
---|---|
bin | 111110110010001000001… |
… | …000100011110001001001 |
3 | 120021110022010022002021212 |
4 | 332302020020203301021 |
5 | 1031141423331011332 |
6 | 13102004451542505 |
7 | 623464424230214 |
oct | 76621010436111 |
9 | 16243263262255 |
10 | 4314431110217 |
11 | 1413815980638 |
12 | 5981ba2baa35 |
13 | 253b0664abc7 |
14 | 10cb68cda77b |
15 | 773655588b2 |
hex | 3ec88223c49 |
4314431110217 has 2 divisors, whose sum is σ = 4314431110218. Its totient is φ = 4314431110216.
The previous prime is 4314431110189. The next prime is 4314431110237. The reversal of 4314431110217 is 7120111344134.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3603072126976 + 711358983241 = 1898176^2 + 843421^2 .
It is a cyclic number.
It is not a de Polignac number, because 4314431110217 - 210 = 4314431109193 is a prime.
It is a super-3 number, since 3×43144311102173 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (4314431110237) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2157215555108 + 2157215555109.
It is an arithmetic number, because the mean of its divisors is an integer number (2157215555109).
Almost surely, 24314431110217 is an apocalyptic number.
It is an amenable number.
4314431110217 is a deficient number, since it is larger than the sum of its proper divisors (1).
4314431110217 is an equidigital number, since it uses as much as digits as its factorization.
4314431110217 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8064, while the sum is 32.
The spelling of 4314431110217 in words is "four trillion, three hundred fourteen billion, four hundred thirty-one million, one hundred ten thousand, two hundred seventeen".
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