Base | Representation |
---|---|
bin | 10011100111110101110001… |
… | …11100011011100111011001 |
3 | 12122210010120200112022110101 |
4 | 21303322320330123213121 |
5 | 21123433401120230423 |
6 | 231434554452015401 |
7 | 12042336520600063 |
oct | 1163727074334731 |
9 | 178703520468411 |
10 | 43150344305113 |
11 | 12826a5a484481 |
12 | 4a0a9ab001561 |
13 | 1b100a1ab7b46 |
14 | a926b878a733 |
15 | 4ec68d3a17ad |
hex | 273eb8f1b9d9 |
43150344305113 has 2 divisors, whose sum is σ = 43150344305114. Its totient is φ = 43150344305112.
The previous prime is 43150344305077. The next prime is 43150344305161. The reversal of 43150344305113 is 31150344305134.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 42578796209049 + 571548096064 = 6525243^2 + 756008^2 .
It is a cyclic number.
It is not a de Polignac number, because 43150344305113 - 225 = 43150310750681 is a prime.
It is not a weakly prime, because it can be changed into another prime (43150344305183) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21575172152556 + 21575172152557.
It is an arithmetic number, because the mean of its divisors is an integer number (21575172152557).
Almost surely, 243150344305113 is an apocalyptic number.
It is an amenable number.
43150344305113 is a deficient number, since it is larger than the sum of its proper divisors (1).
43150344305113 is an equidigital number, since it uses as much as digits as its factorization.
43150344305113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 129600, while the sum is 37.
The spelling of 43150344305113 in words is "forty-three trillion, one hundred fifty billion, three hundred forty-four million, three hundred five thousand, one hundred thirteen".
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