Base | Representation |
---|---|
bin | 1000000010101010… |
… | …10110000100110001 |
3 | 102010212211121000202 |
4 | 10001111112010301 |
5 | 32320214334303 |
6 | 1552223324545 |
7 | 211662532643 |
oct | 40125260461 |
9 | 12125747022 |
10 | 4317339953 |
11 | 1916031453 |
12 | a05a50755 |
13 | 53a5b0c34 |
14 | 2cd55c893 |
15 | 1a405bc88 |
hex | 101556131 |
4317339953 has 2 divisors, whose sum is σ = 4317339954. Its totient is φ = 4317339952.
The previous prime is 4317339889. The next prime is 4317339989. The reversal of 4317339953 is 3599337134.
4317339953 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3472391329 + 844948624 = 58927^2 + 29068^2 .
It is a cyclic number.
It is not a de Polignac number, because 4317339953 - 26 = 4317339889 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 4317339898 and 4317339907.
It is not a weakly prime, because it can be changed into another prime (4317332953) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2158669976 + 2158669977.
It is an arithmetic number, because the mean of its divisors is an integer number (2158669977).
Almost surely, 24317339953 is an apocalyptic number.
It is an amenable number.
4317339953 is a deficient number, since it is larger than the sum of its proper divisors (1).
4317339953 is an equidigital number, since it uses as much as digits as its factorization.
4317339953 is an evil number, because the sum of its binary digits is even.
The product of its digits is 918540, while the sum is 47.
The square root of 4317339953 is about 65706.4681214871. The cubic root of 4317339953 is about 1628.3162199129.
The spelling of 4317339953 in words is "four billion, three hundred seventeen million, three hundred thirty-nine thousand, nine hundred fifty-three".
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