4320131412433 has 4 divisors (see below), whose sum is σ = 4320137222208. Its totient is φ = 4320125602660.

The previous prime is 4320131412431. The next prime is 4320131412449. The reversal of 4320131412433 is 3342141310234.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 4320131412433 - 2¹ = 4320131412431 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 4320131412395 and 4320131412404.

It is not an unprimeable number, because it can be changed into a prime (4320131412431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1591573 + ... + 3342658.

It is an arithmetic number, because the mean of its divisors is an integer number (1080034305552).

Almost surely, 2^{4320131412433} is an apocalyptic number.

It is an amenable number.

4320131412433 is a deficient number, since it is larger than the sum of its proper divisors (5809775).

4320131412433 is an equidigital number, since it uses as much as digits as its factorization.

4320131412433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5809774.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 4320131412433 its reverse (3342141310234), we get a palindrome (7662272722667).

The spelling of 4320131412433 in words is "four trillion, three hundred twenty billion, one hundred thirty-one million, four hundred twelve thousand, four hundred thirty-three".