Base | Representation |
---|---|
bin | 111110110111011100100… |
… | …111010010111001001001 |
3 | 120022000001020000112112221 |
4 | 332313130213102321021 |
5 | 1031240123203433001 |
6 | 13104351350334041 |
7 | 624056116121422 |
oct | 76673447227111 |
9 | 16260036015487 |
10 | 4320143421001 |
11 | 1416187376241 |
12 | 59933335a321 |
13 | 254506c39465 |
14 | 10d14b81c649 |
15 | 7759bcb51a1 |
hex | 3eddc9d2e49 |
4320143421001 has 4 divisors (see below), whose sum is σ = 4320715860432. Its totient is φ = 4319570981572.
The previous prime is 4320143420987. The next prime is 4320143421029. The reversal of 4320143421001 is 1001243410234.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 4320143421001 - 215 = 4320143388233 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (4320143421401) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 286208395 + ... + 286223488.
It is an arithmetic number, because the mean of its divisors is an integer number (1080178965108).
Almost surely, 24320143421001 is an apocalyptic number.
It is an amenable number.
4320143421001 is a deficient number, since it is larger than the sum of its proper divisors (572439431).
4320143421001 is an equidigital number, since it uses as much as digits as its factorization.
4320143421001 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 572439430.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 4320143421001 its reverse (1001243410234), we get a palindrome (5321386831235).
The spelling of 4320143421001 in words is "four trillion, three hundred twenty billion, one hundred forty-three million, four hundred twenty-one thousand, one".
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