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43203100130257 is a prime number
BaseRepresentation
bin10011101001011000000010…
…11011111011101111010001
312122222011202022220220111011
421310230001123323233101
521130314422113132012
6231515121420250521
712046215044654344
oct1164540133735721
9178864668826434
1043203100130257
11128473717a2771
124a190729a0a41
131b1505b788c22
14a950810c245b
154edc29b571a7
hex274b016fbbd1

43203100130257 has 2 divisors, whose sum is σ = 43203100130258. Its totient is φ = 43203100130256.

The previous prime is 43203100130171. The next prime is 43203100130293. The reversal of 43203100130257 is 75203100130234.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 27657932964561 + 15545167165696 = 5259081^2 + 3942736^2 .

It is a cyclic number.

It is not a de Polignac number, because 43203100130257 - 219 = 43203099605969 is a prime.

It is not a weakly prime, because it can be changed into another prime (43203100130657) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21601550065128 + 21601550065129.

It is an arithmetic number, because the mean of its divisors is an integer number (21601550065129).

Almost surely, 243203100130257 is an apocalyptic number.

It is an amenable number.

43203100130257 is a deficient number, since it is larger than the sum of its proper divisors (1).

43203100130257 is an equidigital number, since it uses as much as digits as its factorization.

43203100130257 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15120, while the sum is 31.

The spelling of 43203100130257 in words is "forty-three trillion, two hundred three billion, one hundred million, one hundred thirty thousand, two hundred fifty-seven".