Base | Representation |
---|---|
bin | 110001000111011101101100… |
… | …1101111001100001100101001 |
3 | 2002122201002100002120002021202 |
4 | 1202032323121233030030221 |
5 | 423111422434303044431 |
6 | 4130505511452213545 |
7 | 160000312341326450 |
oct | 14216733157141451 |
9 | 2078632302502252 |
10 | 432034413331241 |
11 | 115728847236656 |
12 | 405571b6a6a2b5 |
13 | 1570b893a36356 |
14 | 7898811ab7b97 |
15 | 34e33171cc8cb |
hex | 188eed9bcc329 |
432034413331241 has 4 divisors (see below), whose sum is σ = 493753615235712. Its totient is φ = 370315211426772.
The previous prime is 432034413331153. The next prime is 432034413331247. The reversal of 432034413331241 is 142133314430234.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 432034413331241 - 234 = 432017233462057 is a prime.
It is a super-2 number, since 2×4320344133312412 (a number of 30 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 432034413331195 and 432034413331204.
It is not an unprimeable number, because it can be changed into a prime (432034413331247) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 30859600952225 + ... + 30859600952238.
It is an arithmetic number, because the mean of its divisors is an integer number (123438403808928).
Almost surely, 2432034413331241 is an apocalyptic number.
It is an amenable number.
432034413331241 is a deficient number, since it is larger than the sum of its proper divisors (61719201904471).
432034413331241 is an equidigital number, since it uses as much as digits as its factorization.
432034413331241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 61719201904470.
The product of its (nonzero) digits is 248832, while the sum is 38.
Adding to 432034413331241 its reverse (142133314430234), we get a palindrome (574167727761475).
The spelling of 432034413331241 in words is "four hundred thirty-two trillion, thirty-four billion, four hundred thirteen million, three hundred thirty-one thousand, two hundred forty-one".
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