Base | Representation |
---|---|
bin | 111110111011010111101… |
… | …001101001101111111001 |
3 | 120022101220202002000121020 |
4 | 332323113221221233321 |
5 | 1031322234402320441 |
6 | 13110325321533053 |
7 | 624265360016541 |
oct | 76732751515771 |
9 | 16271822060536 |
10 | 4324355120121 |
11 | 1417a48803113 |
12 | 59a109944189 |
13 | 254a2868020a |
14 | 10d42ad1c321 |
15 | 77746905e66 |
hex | 3eed7a69bf9 |
4324355120121 has 4 divisors (see below), whose sum is σ = 5765806826832. Its totient is φ = 2882903413412.
The previous prime is 4324355120089. The next prime is 4324355120221. The reversal of 4324355120121 is 1210215534234.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 4324355120121 - 25 = 4324355120089 is a prime.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (4324355120221) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 720725853351 + ... + 720725853356.
It is an arithmetic number, because the mean of its divisors is an integer number (1441451706708).
Almost surely, 24324355120121 is an apocalyptic number.
It is an amenable number.
4324355120121 is a deficient number, since it is larger than the sum of its proper divisors (1441451706711).
4324355120121 is a wasteful number, since it uses less digits than its factorization.
4324355120121 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1441451706710.
The product of its (nonzero) digits is 28800, while the sum is 33.
The spelling of 4324355120121 in words is "four trillion, three hundred twenty-four billion, three hundred fifty-five million, one hundred twenty thousand, one hundred twenty-one".
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