Base | Representation |
---|---|
bin | 10011101010100100011110… |
… | …00100011010010100101011 |
3 | 12200010002122211210210121222 |
4 | 21311102033010122110223 |
5 | 21132002440021100121 |
6 | 231550025103052255 |
7 | 12052166610621536 |
oct | 1165221704322453 |
9 | 180102584723558 |
10 | 43244131034411 |
11 | 1286280766230a |
12 | 4a25003ba108b |
13 | 1b18b9a2a9038 |
14 | a97054563a1d |
15 | 4eed2bdc70ab |
hex | 27548f11a52b |
43244131034411 has 2 divisors, whose sum is σ = 43244131034412. Its totient is φ = 43244131034410.
The previous prime is 43244131034359. The next prime is 43244131034471. The reversal of 43244131034411 is 11443013144234.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 43244131034411 - 210 = 43244131033387 is a prime.
It is a super-2 number, since 2×432441310344112 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (43244131034471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21622065517205 + 21622065517206.
It is an arithmetic number, because the mean of its divisors is an integer number (21622065517206).
Almost surely, 243244131034411 is an apocalyptic number.
43244131034411 is a deficient number, since it is larger than the sum of its proper divisors (1).
43244131034411 is an equidigital number, since it uses as much as digits as its factorization.
43244131034411 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 55296, while the sum is 35.
Adding to 43244131034411 its reverse (11443013144234), we get a palindrome (54687144178645).
The spelling of 43244131034411 in words is "forty-three trillion, two hundred forty-four billion, one hundred thirty-one million, thirty-four thousand, four hundred eleven".
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