Base | Representation |
---|---|
bin | 111111000000101111011… |
… | …000110000100110010011 |
3 | 120022221210122120121201012 |
4 | 333000233120300212103 |
5 | 1031421042221212120 |
6 | 13113121451201135 |
7 | 624561314112131 |
oct | 77005730604623 |
9 | 16287718517635 |
10 | 4330122054035 |
11 | 141a4380169a8 |
12 | 59b2591461ab |
13 | 25543738524b |
14 | 10d816bbc751 |
15 | 77982d521c5 |
hex | 3f02f630993 |
4330122054035 has 32 divisors (see below), whose sum is σ = 5250604248000. Its totient is φ = 3427897245696.
The previous prime is 4330122054019. The next prime is 4330122054047. The reversal of 4330122054035 is 5304502210334.
4330122054035 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 4330122054035 - 24 = 4330122054019 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 4330122053992 and 4330122054010.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1328664236 + ... + 1328667494.
It is an arithmetic number, because the mean of its divisors is an integer number (164081382750).
Almost surely, 24330122054035 is an apocalyptic number.
4330122054035 is a deficient number, since it is larger than the sum of its proper divisors (920482193965).
4330122054035 is a wasteful number, since it uses less digits than its factorization.
4330122054035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6455.
The product of its (nonzero) digits is 43200, while the sum is 32.
Adding to 4330122054035 its reverse (5304502210334), we get a palindrome (9634624264369).
The spelling of 4330122054035 in words is "four trillion, three hundred thirty billion, one hundred twenty-two million, fifty-four thousand, thirty-five".
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