Base | Representation |
---|---|
bin | 10011101100010111000011… |
… | …00110000001101000001011 |
3 | 12200022222102212102010100122 |
4 | 21312023201212001220023 |
5 | 21134004430122320021 |
6 | 232034201055253455 |
7 | 12056505154001141 |
oct | 1166134146015013 |
9 | 180288385363318 |
10 | 43305645120011 |
11 | 1288690377028a |
12 | 4a34b10b1a28b |
13 | 1b2192161a861 |
14 | a9a00c145591 |
15 | 50172c507bab |
hex | 2762e1981a0b |
43305645120011 has 2 divisors, whose sum is σ = 43305645120012. Its totient is φ = 43305645120010.
The previous prime is 43305645119861. The next prime is 43305645120061. The reversal of 43305645120011 is 11002154650334.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-43305645120011 is a prime.
It is not a weakly prime, because it can be changed into another prime (43305645120061) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21652822560005 + 21652822560006.
It is an arithmetic number, because the mean of its divisors is an integer number (21652822560006).
Almost surely, 243305645120011 is an apocalyptic number.
43305645120011 is a deficient number, since it is larger than the sum of its proper divisors (1).
43305645120011 is an equidigital number, since it uses as much as digits as its factorization.
43305645120011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 43200, while the sum is 35.
Adding to 43305645120011 its reverse (11002154650334), we get a palindrome (54307799770345).
The spelling of 43305645120011 in words is "forty-three trillion, three hundred five billion, six hundred forty-five million, one hundred twenty thousand, eleven".
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