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4331102451161 = 5950972780629
BaseRepresentation
bin111111000001101001110…
…100101011010111011001
3120100001022222100221201212
4333001221310223113121
51031430044211414121
613113403032352505
7624624520256603
oct77015164532731
916301288327655
104331102451161
11141a8a0470862
1259b491545735
1325556251a9a5
1410d8ab0a6173
15779dde6025b
hex3f069d2b5d9

4331102451161 has 4 divisors (see below), whose sum is σ = 4331175291300. Its totient is φ = 4331029611024.

The previous prime is 4331102451149. The next prime is 4331102451211. The reversal of 4331102451161 is 1611542011334.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 333801995536 + 3997300455625 = 577756^2 + 1999325^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4331102451161 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4331102451961) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 36330806 + ... + 36449823.

It is an arithmetic number, because the mean of its divisors is an integer number (1082793822825).

Almost surely, 24331102451161 is an apocalyptic number.

It is an amenable number.

4331102451161 is a deficient number, since it is larger than the sum of its proper divisors (72840139).

4331102451161 is an equidigital number, since it uses as much as digits as its factorization.

4331102451161 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 72840138.

The product of its (nonzero) digits is 8640, while the sum is 32.

Adding to 4331102451161 its reverse (1611542011334), we get a palindrome (5942644462495).

The spelling of 4331102451161 in words is "four trillion, three hundred thirty-one billion, one hundred two million, four hundred fifty-one thousand, one hundred sixty-one".

Divisors: 1 59509 72780629 4331102451161