Base | Representation |
---|---|
bin | 10011101100100001001111… |
… | …11110111001000101100011 |
3 | 12200100111120111021012200121 |
4 | 21312100213332321011203 |
5 | 21134102133434323133 |
6 | 232040504310501111 |
7 | 12060060645211054 |
oct | 1166204776710543 |
9 | 180314514235617 |
10 | 43311121011043 |
11 | 12889163768266 |
12 | 4a35b9a964797 |
13 | 1b222b4c3ca72 |
14 | a9a3ab4c472b |
15 | 50194d11402d |
hex | 276427fb9163 |
43311121011043 has 4 divisors (see below), whose sum is σ = 43311155825808. Its totient is φ = 43311086196280.
The previous prime is 43311121010929. The next prime is 43311121011049. The reversal of 43311121011043 is 34011012111334.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 43311121011043 - 221 = 43311118913891 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 43311121010999 and 43311121011017.
It is not an unprimeable number, because it can be changed into a prime (43311121011049) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15469396 + ... + 18053377.
It is an arithmetic number, because the mean of its divisors is an integer number (10827788956452).
Almost surely, 243311121011043 is an apocalyptic number.
43311121011043 is a deficient number, since it is larger than the sum of its proper divisors (34814765).
43311121011043 is a wasteful number, since it uses less digits than its factorization.
43311121011043 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 34814764.
The product of its (nonzero) digits is 864, while the sum is 25.
Adding to 43311121011043 its reverse (34011012111334), we get a palindrome (77322133122377).
The spelling of 43311121011043 in words is "forty-three trillion, three hundred eleven billion, one hundred twenty-one million, eleven thousand, forty-three".
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