43311411323 has 2 divisors, whose sum is σ = 43311411324. Its totient is φ = 43311411322.

The previous prime is 43311411301. The next prime is 43311411359. The reversal of 43311411323 is 32311411334.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 43311411323 - 2¹⁶ = 43311345787 is a prime.

It is a super-2 number, since 2×43311411323² (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 43311411292 and 43311411301.

It is not a weakly prime, because it can be changed into another prime (43311411223) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21655705661 + 21655705662.

It is an arithmetic number, because the mean of its divisors is an integer number (21655705662).

Almost surely, 2^43311411323 is an apocalyptic number.

43311411323 is a deficient number, since it is larger than the sum of its proper divisors (1).

43311411323 is an equidigital number, since it uses as much as digits as its factorization.

43311411323 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2592, while the sum is 26.

Adding to 43311411323 its reverse (32311411334), we get a palindrome (75622822657).

The spelling of 43311411323 in words is "forty-three billion, three hundred eleven million, four hundred eleven thousand, three hundred twenty-three".