Base | Representation |
---|---|
bin | 101000010101100110… |
… | …001011010101110111 |
3 | 11010210111011200200220 |
4 | 220111212023111313 |
5 | 1202200333034143 |
6 | 31521450305423 |
7 | 3062211642354 |
oct | 502546132567 |
9 | 133714150626 |
10 | 43312002423 |
11 | 17406550528 |
12 | 8489128273 |
13 | 41132a7a01 |
14 | 214c3cd62b |
15 | 11d765ad83 |
hex | a1598b577 |
43312002423 has 16 divisors (see below), whose sum is σ = 59234517216. Its totient is φ = 28133903360.
The previous prime is 43312002421. The next prime is 43312002431. The reversal of 43312002423 is 32420021334.
It is a cyclic number.
It is not a de Polignac number, because 43312002423 - 21 = 43312002421 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 43312002393 and 43312002402.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (43312002421) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 132690 + ... + 322847.
It is an arithmetic number, because the mean of its divisors is an integer number (3702157326).
Almost surely, 243312002423 is an apocalyptic number.
43312002423 is a deficient number, since it is larger than the sum of its proper divisors (15922514793).
43312002423 is a wasteful number, since it uses less digits than its factorization.
43312002423 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 456354.
The product of its (nonzero) digits is 3456, while the sum is 24.
Adding to 43312002423 its reverse (32420021334), we get a palindrome (75732023757).
The spelling of 43312002423 in words is "forty-three billion, three hundred twelve million, two thousand, four hundred twenty-three".
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