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43312002423 = 341773455537
BaseRepresentation
bin101000010101100110…
…001011010101110111
311010210111011200200220
4220111212023111313
51202200333034143
631521450305423
73062211642354
oct502546132567
9133714150626
1043312002423
1117406550528
128489128273
1341132a7a01
14214c3cd62b
1511d765ad83
hexa1598b577

43312002423 has 16 divisors (see below), whose sum is σ = 59234517216. Its totient is φ = 28133903360.

The previous prime is 43312002421. The next prime is 43312002431. The reversal of 43312002423 is 32420021334.

It is a cyclic number.

It is not a de Polignac number, because 43312002423 - 21 = 43312002421 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 43312002393 and 43312002402.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (43312002421) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 132690 + ... + 322847.

It is an arithmetic number, because the mean of its divisors is an integer number (3702157326).

Almost surely, 243312002423 is an apocalyptic number.

43312002423 is a deficient number, since it is larger than the sum of its proper divisors (15922514793).

43312002423 is a wasteful number, since it uses less digits than its factorization.

43312002423 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 456354.

The product of its (nonzero) digits is 3456, while the sum is 24.

Adding to 43312002423 its reverse (32420021334), we get a palindrome (75732023757).

The spelling of 43312002423 in words is "forty-three billion, three hundred twelve million, two thousand, four hundred twenty-three".

Divisors: 1 3 41 123 773 2319 31693 95079 455537 1366611 18677017 56031051 352130101 1056390303 14437334141 43312002423