Base | Representation |
---|---|
bin | 111111000001110101110… |
… | …011010110011110100001 |
3 | 120100001211222112201221101 |
4 | 333001311303112132201 |
5 | 1031431002134230144 |
6 | 13113435012154401 |
7 | 624632510462101 |
oct | 77016563263641 |
9 | 16301758481841 |
10 | 4331303430049 |
11 | 141a993962212 |
12 | 59b528908a01 |
13 | 2555950586cb |
14 | 10d8c9a61201 |
15 | 77a0190e6d4 |
hex | 3f075cd67a1 |
4331303430049 has 2 divisors, whose sum is σ = 4331303430050. Its totient is φ = 4331303430048.
The previous prime is 4331303430007. The next prime is 4331303430071. The reversal of 4331303430049 is 9400343031334.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2315059627024 + 2016243803025 = 1521532^2 + 1419945^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4331303430049 is a prime.
It is a super-2 number, since 2×43313034300492 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (4331303433049) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2165651715024 + 2165651715025.
It is an arithmetic number, because the mean of its divisors is an integer number (2165651715025).
Almost surely, 24331303430049 is an apocalyptic number.
It is an amenable number.
4331303430049 is a deficient number, since it is larger than the sum of its proper divisors (1).
4331303430049 is an equidigital number, since it uses as much as digits as its factorization.
4331303430049 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 139968, while the sum is 37.
The spelling of 4331303430049 in words is "four trillion, three hundred thirty-one billion, three hundred three million, four hundred thirty thousand, forty-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •