Base | Representation |
---|---|
bin | 101000010101101010… |
… | …011100100000101011 |
3 | 11010210120021112112122 |
4 | 220111222130200223 |
5 | 1202201124340243 |
6 | 31521530301455 |
7 | 3062224312433 |
oct | 502552344053 |
9 | 133716245478 |
10 | 43313121323 |
11 | 1740714513a |
12 | 848958788b |
13 | 41135aa094 |
14 | 214c6012c3 |
15 | 11d77cc668 |
hex | a15a9c82b |
43313121323 has 4 divisors (see below), whose sum is σ = 43733637168. Its totient is φ = 42892605480.
The previous prime is 43313121287. The next prime is 43313121329. The reversal of 43313121323 is 32312131334.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 43313121323 - 234 = 26133252139 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 43313121292 and 43313121301.
It is not an unprimeable number, because it can be changed into a prime (43313121329) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 210257768 + ... + 210257973.
It is an arithmetic number, because the mean of its divisors is an integer number (10933409292).
Almost surely, 243313121323 is an apocalyptic number.
43313121323 is a deficient number, since it is larger than the sum of its proper divisors (420515845).
43313121323 is a wasteful number, since it uses less digits than its factorization.
43313121323 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 420515844.
The product of its digits is 3888, while the sum is 26.
Adding to 43313121323 its reverse (32312131334), we get a palindrome (75625252657).
It can be divided in two parts, 433131 and 21323, that added together give a palindrome (454454).
The spelling of 43313121323 in words is "forty-three billion, three hundred thirteen million, one hundred twenty-one thousand, three hundred twenty-three".
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