4331401440001 has 4 divisors (see below), whose sum is σ = 4437045377604. Its totient is φ = 4225757502400.

The previous prime is 4331401439977. The next prime is 4331401440049. The reversal of 4331401440001 is 1000441041334.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 2345982355600 + 1985419084401 = 1531660^2 + 1409049^2 .

It is a cyclic number.

It is not a de Polignac number, because 4331401440001 - 2¹¹ = 4331401437953 is a prime.

It is a super-2 number, since 2×4331401440001² (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4331401440071) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 52821968740 + ... + 52821968821.

It is an arithmetic number, because the mean of its divisors is an integer number (1109261344401).

Almost surely, 2^{4331401440001} is an apocalyptic number.

4331401440001 is a gapful number since it is divisible by the number (41) formed by its first and last digit.

It is an amenable number.

4331401440001 is a deficient number, since it is larger than the sum of its proper divisors (105643937603).

4331401440001 is a wasteful number, since it uses less digits than its factorization.

4331401440001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 105643937602.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 4331401440001 its reverse (1000441041334), we get a palindrome (5331842481335).

The spelling of 4331401440001 in words is "four trillion, three hundred thirty-one billion, four hundred one million, four hundred forty thousand, one".