43314140212033 has 4 divisors (see below), whose sum is σ = 45593831802160. Its totient is φ = 41034448621908.

The previous prime is 43314140212009. The next prime is 43314140212067. The reversal of 43314140212033 is 33021204141334.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 43314140212033 - 2⁵ = 43314140212001 is a prime.

It is a super-2 number, since 2×43314140212033² (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 43314140211986 and 43314140212004.

It is not an unprimeable number, because it can be changed into a prime (43314140212333) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1139845795035 + ... + 1139845795072.

It is an arithmetic number, because the mean of its divisors is an integer number (11398457950540).

Almost surely, 2^{43314140212033} is an apocalyptic number.

It is an amenable number.

43314140212033 is a deficient number, since it is larger than the sum of its proper divisors (2279691590127).

43314140212033 is a wasteful number, since it uses less digits than its factorization.

43314140212033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2279691590126.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 43314140212033 its reverse (33021204141334), we get a palindrome (76335344353367).

The spelling of 43314140212033 in words is "forty-three trillion, three hundred fourteen billion, one hundred forty million, two hundred twelve thousand, thirty-three".