Base | Representation |
---|---|
bin | 10011101100100111000011… |
… | …11001011001110100000010 |
3 | 12200100210121212110002112222 |
4 | 21312103201321121310002 |
5 | 21134130030433300102 |
6 | 232042142012251042 |
7 | 12060231151264136 |
oct | 1166234171316402 |
9 | 180323555402488 |
10 | 43314240134402 |
11 | 1288a5143a0866 |
12 | 4a3670b470a82 |
13 | 1b226912021a3 |
14 | a9a5c58593c6 |
15 | 501a81d88aa2 |
hex | 2764e1e59d02 |
43314240134402 has 4 divisors (see below), whose sum is σ = 64971360201606. Its totient is φ = 21657120067200.
The previous prime is 43314240134393. The next prime is 43314240134443. The reversal of 43314240134402 is 20443104241334.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 28294112046841 + 15020128087561 = 5319221^2 + 3875581^2 .
It is a super-2 number, since 2×433142401344022 (a number of 28 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10828560033599 + ... + 10828560033602.
Almost surely, 243314240134402 is an apocalyptic number.
43314240134402 is a deficient number, since it is larger than the sum of its proper divisors (21657120067204).
43314240134402 is a wasteful number, since it uses less digits than its factorization.
43314240134402 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 21657120067203.
The product of its (nonzero) digits is 110592, while the sum is 35.
Adding to 43314240134402 its reverse (20443104241334), we get a palindrome (63757344375736).
The spelling of 43314240134402 in words is "forty-three trillion, three hundred fourteen billion, two hundred forty million, one hundred thirty-four thousand, four hundred two".
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