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4331432001 = 3131036910711
BaseRepresentation
bin1000000100010110…
…00110100001000001
3102011212100112200110
410002023012201001
532332321311001
61553445341533
7212223364431
oct40213064101
912155315613
104331432001
111922a86a76
12a0a7078a9
135404a6220
142d138a2c1
151a53e23d6
hex1022c6841

4331432001 has 16 divisors (see below), whose sum is σ = 6220672640. Its totient is φ = 2664990720.

The previous prime is 4331431981. The next prime is 4331432009. The reversal of 4331432001 is 1002341334.

It is not a de Polignac number, because 4331432001 - 27 = 4331431873 is a prime.

It is a super-2 number, since 2×43314320012 = 37522606358573728002, which contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (4331432009) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 399036 + ... + 409746.

It is an arithmetic number, because the mean of its divisors is an integer number (388792040).

Almost surely, 24331432001 is an apocalyptic number.

It is an amenable number.

4331432001 is a deficient number, since it is larger than the sum of its proper divisors (1889240639).

4331432001 is a wasteful number, since it uses less digits than its factorization.

4331432001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 21096.

The product of its (nonzero) digits is 864, while the sum is 21.

The square root of 4331432001 is about 65813.6156201739. The cubic root of 4331432001 is about 1630.0859353491.

Adding to 4331432001 its reverse (1002341334), we get a palindrome (5333773335).

The spelling of 4331432001 in words is "four billion, three hundred thirty-one million, four hundred thirty-two thousand, one".

Divisors: 1 3 13 39 10369 10711 31107 32133 134797 139243 404391 417729 111062359 333187077 1443810667 4331432001