Base | Representation |
---|---|
bin | 111111000010000001110… |
… | …001010011011110011101 |
3 | 120100002100222100221001111 |
4 | 333002001301103132131 |
5 | 1031431410040020221 |
6 | 13113510543542021 |
7 | 624640466246524 |
oct | 77020161233635 |
9 | 16302328327044 |
10 | 4331504220061 |
11 | 141aa87234777 |
12 | 59b583bba911 |
13 | 2555c782b475 |
14 | 10d9085ab4bb |
15 | 77a14372be1 |
hex | 3f081c5379d |
4331504220061 has 16 divisors (see below), whose sum is σ = 4654316851200. Its totient is φ = 4018940982000.
The previous prime is 4331504220037. The next prime is 4331504220067. The reversal of 4331504220061 is 1600224051334.
It is a cyclic number.
It is not a de Polignac number, because 4331504220061 - 213 = 4331504211869 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4331504220067) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 10428421 + ... + 10835818.
It is an arithmetic number, because the mean of its divisors is an integer number (290894803200).
Almost surely, 24331504220061 is an apocalyptic number.
It is an amenable number.
4331504220061 is a deficient number, since it is larger than the sum of its proper divisors (322812631139).
4331504220061 is a wasteful number, since it uses less digits than its factorization.
4331504220061 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 21264480.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 4331504220061 its reverse (1600224051334), we get a palindrome (5931728271395).
The spelling of 4331504220061 in words is "four trillion, three hundred thirty-one billion, five hundred four million, two hundred twenty thousand, sixty-one".
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