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4331504220061 = 197115121264239
BaseRepresentation
bin111111000010000001110…
…001010011011110011101
3120100002100222100221001111
4333002001301103132131
51031431410040020221
613113510543542021
7624640466246524
oct77020161233635
916302328327044
104331504220061
11141aa87234777
1259b583bba911
132555c782b475
1410d9085ab4bb
1577a14372be1
hex3f081c5379d

4331504220061 has 16 divisors (see below), whose sum is σ = 4654316851200. Its totient is φ = 4018940982000.

The previous prime is 4331504220037. The next prime is 4331504220067. The reversal of 4331504220061 is 1600224051334.

It is a cyclic number.

It is not a de Polignac number, because 4331504220061 - 213 = 4331504211869 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4331504220067) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 10428421 + ... + 10835818.

It is an arithmetic number, because the mean of its divisors is an integer number (290894803200).

Almost surely, 24331504220061 is an apocalyptic number.

It is an amenable number.

4331504220061 is a deficient number, since it is larger than the sum of its proper divisors (322812631139).

4331504220061 is a wasteful number, since it uses less digits than its factorization.

4331504220061 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 21264480.

The product of its (nonzero) digits is 17280, while the sum is 31.

Adding to 4331504220061 its reverse (1600224051334), we get a palindrome (5931728271395).

The spelling of 4331504220061 in words is "four trillion, three hundred thirty-one billion, five hundred four million, two hundred twenty thousand, sixty-one".

Divisors: 1 19 71 151 1349 2869 10721 203699 21264239 404020541 1509760969 3210900089 28685458411 61007101691 227973906319 4331504220061