Base | Representation |
---|---|
bin | 111111000010100110000… |
… | …011100111101100011001 |
3 | 120100010221101220012211121 |
4 | 333002212003213230121 |
5 | 1031434131412014431 |
6 | 13114051212125241 |
7 | 624661540641004 |
oct | 77024603475431 |
9 | 16303841805747 |
10 | 4332113001241 |
11 | 1420269940013 |
12 | 59b713a66821 |
13 | 2556939acc0c |
14 | 10d96539c53b |
15 | 77a4ca27611 |
hex | 3f0a60e7b19 |
4332113001241 has 4 divisors (see below), whose sum is σ = 4332391269300. Its totient is φ = 4331834733184.
The previous prime is 4332113001239. The next prime is 4332113001247. The reversal of 4332113001241 is 1421003112334.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 2796992001241 + 1535121000000 = 1672421^2 + 1239000^2 .
It is a cyclic number.
It is not a de Polignac number, because 4332113001241 - 21 = 4332113001239 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (4332113001247) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 139110676 + ... + 139141813.
It is an arithmetic number, because the mean of its divisors is an integer number (1083097817325).
Almost surely, 24332113001241 is an apocalyptic number.
It is an amenable number.
4332113001241 is a deficient number, since it is larger than the sum of its proper divisors (278268059).
4332113001241 is a wasteful number, since it uses less digits than its factorization.
4332113001241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 278268058.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 4332113001241 its reverse (1421003112334), we get a palindrome (5753116113575).
The spelling of 4332113001241 in words is "four trillion, three hundred thirty-two billion, one hundred thirteen million, one thousand, two hundred forty-one".
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