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4332113001241 = 15569278252489
BaseRepresentation
bin111111000010100110000…
…011100111101100011001
3120100010221101220012211121
4333002212003213230121
51031434131412014431
613114051212125241
7624661540641004
oct77024603475431
916303841805747
104332113001241
111420269940013
1259b713a66821
132556939acc0c
1410d96539c53b
1577a4ca27611
hex3f0a60e7b19

4332113001241 has 4 divisors (see below), whose sum is σ = 4332391269300. Its totient is φ = 4331834733184.

The previous prime is 4332113001239. The next prime is 4332113001247. The reversal of 4332113001241 is 1421003112334.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 2796992001241 + 1535121000000 = 1672421^2 + 1239000^2 .

It is a cyclic number.

It is not a de Polignac number, because 4332113001241 - 21 = 4332113001239 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4332113001247) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 139110676 + ... + 139141813.

It is an arithmetic number, because the mean of its divisors is an integer number (1083097817325).

Almost surely, 24332113001241 is an apocalyptic number.

It is an amenable number.

4332113001241 is a deficient number, since it is larger than the sum of its proper divisors (278268059).

4332113001241 is a wasteful number, since it uses less digits than its factorization.

4332113001241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 278268058.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 4332113001241 its reverse (1421003112334), we get a palindrome (5753116113575).

The spelling of 4332113001241 in words is "four trillion, three hundred thirty-two billion, one hundred thirteen million, one thousand, two hundred forty-one".

Divisors: 1 15569 278252489 4332113001241